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So U(f) = L(f) = 0 are equal, and the integral of f is 0 In this example, the infimum of the upper Riemann sums is not attained and U(f;P) > U(f) for every partition P A similar argument shows that a function f a,b → Rthat is zero except at (1,IPosted 5/9/14 1121 PM, 26 messages±Z v } u o Ç Z µ ( ( o v µ } Z v P Z } ±/ v o Ì W V ( } o o Á P Z v o o o Ç U ê


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